线圈匝数W与其中电流I的乘积，即WI称为磁动势。
以下程序段的输出结果是（） int x，i； for（i=1；i<=100；i++） {x=i； if（++x%2==0） if（++x%3==0） if（++x%7==0） printf（"%d"，x）；}
I was busy with my paper when I heard someone（）in the room above.
I am someone who can adapt to any situation. 这句话对应的汉语是_____。
When someone says: “I’m sorry to hear that.”, you may say______.
有以下程序：#include void main(){ int i=0,s=0;for(;;){ if(i==3||i==5) continue;if(i==6)break;i++;s+=i;}cout<
设有int i=0;则以下while循环的执行次数是（ ）while(i<10){ if(i<1) continue;if(i==5) break;i++;}
______, I rock to and fro on the swing. I'm feeling lonely. I wish I had someone to play with.
有以下程序 ,其输出结果是main(){ int x,i;for(i=1;i < =50;i++){ x=i;if(x%2==0)if(x%3==0)if(x%7==0)printf(\%d\,i);}}
I wouldn’t dream _____ marrying someone I hadn’t lived with.
The idiom, “If you believe that, then I have a bridge I want to sell you.” is used to describe someone who is__
以下while循环的次数是 i=0 while i＜10: if i＜1: continue if i==5: break i += 1
听力原文：If you are asking for someone to translate this document, I think the new secretary, who is bilingual, can do the job hand over fist.
听力原文：W: I just found someone's wallet lying in the street. Luckily, the owner's telephone number is inside.
Listen! I her someone English in the next room. [ ]to red B．redC．reding D．redsListen! I her someone English in the next room. [ ]to red B．red C．reding D．reds
I wanted to find someone with______I could discuss books and music.
I need someone to stay with me,just like she did in the past years?中文意思
以下程序的输出结果是（)。main{ int i=0，S=0；for（；；){if（i==3 ||i==5)continue；if（i==6)break；i+
I want a career where I can work with money. I am very good with numbers. Someone who is good with numbers
He is someone I have known quite a while
有以下程序： void main（) int i； for（i=1; i＜=40; 1++) if（i++%3==0) if（i%8==0) printf（"%d",i); printf（""); 执行后输出的结果是（)。
______, I rock to and fro on the swing.I’m feeling lonely.I wish I had someone to
2、下面程序段中while循环的循环次数是（）。 int i=0; while （i＜10) { if （i＜1) continue; if （i==5) break; i++; }
2、以下while循环的次数是 i=0 while i＜10: if i＜1: continue if i==5: break i += 1
