In 'I Wandered Lonely as a Cloud', 'the inward eye' refers to ( ), which is a metaphor to appeal to the reader's imagination of the author's inner feelings.
The Waste Land is written by T. S. Eliot in which the theme of the ( ) of the post-World War I generation is declared to the reader.
The situational irony in the poem “Richard Cory” contradicts the reader’s expectation by ____.
有以下程序 main( ) { int i,s=0; for(i=1;i<10;i++) s=s+i; printf(“%d”,s); } 程序执行后的输出结果是 ( )
阅读以下函数:fun(char s[],char t[]){int i=-1;while(++i,s[i]==t[i]&&s[i]!=’\0’);return(s[i]==’\0’&&t[i]==’\0’);}以上函数的功能是()。
若s=0,执行循环语句”for (i=1;i<=10;i=i+3) s=s+i;”后,i的值为( )。
下面程序的运行结果是 ( )。 #include int main( ) { int i=10,s=0; while(i>0) { if(i%3==0) continue; s=s+i; i--;} printf(\s=%d\,s); return 0; }
To catch the reader’s eyes, an introduction paragraph should __________.
当运行以下程序时,从键盘输入MAYaMaHA,则下面程序的运行结果是( ). main( ) { char s[80],c='a'; int i=0; scanf(\%s\,s); while(s[i]!='\\n') { if(s[i]==c)s[i]=s[i]-32; else if(s[i]==c-32)s[i]=s[i]+32; i++; } puts(s); }
学生读者在图书馆最多可借几册图书(除I类外),其中,借期为几天?可以续借几次?续期为几天?
有以下程序段,运行后 s 的值为( )。 int i, s=0; for(i=1;i<=100;i++) { s=s+i; if(i>10) break;} }
include"stdio.h"main(){int i,s;s=0;for(i=0;i<=10;i++;s=s+i)printf("%d",s);}错误:______改
With the increase in the number of new media advertisements, nowadays, advertiser together with companies _______ competing with others for the reader’s attention.
当运行以下程序时,从键盘输入:AhaMA[空格]Aha<回车>,则下面程序的运行结果是()。 include<stdio.h> int main(void) { char s[80],c='a'; int i=0; scanf("%s",s); while(s[i]!='0') { if(s[i]==c) s[i]=s[i]-32; else if(s[i]==c-32) s[i]=s[i]+32; i++; return 0; } puts(s); }
当运行以下程序时,从键盘输入AhaMA(空格)Aha<CR>,则下面程序的运行结果是include<stdio.h>main(){ char s[80],c=′a′;int i=0;scanf("%s",s);while(s[i]!=′{ if(s[i]==c)s[i]-32;else if(s[i]==c-32)s[i]=s[i]+32;i++; }puts(s); }
执行下面的程序段后,i的值为【 】,s的值为【 】。 s=2 For i=3.2 To 4.9 Step 0.8 s=s+1 Next i Print i, s
main() { int a[5],s,i; for(i=0,s=0;i<5;i++) { scanf("%d",a[i]); s=s+a[i]; } s=s/5;
程序段s=i=0;do{i=i+1;s=s+i;}while(i=n);的时间复杂度为()。
程序段s=i=0;do{i=i+1;s=s+i;}while(i&lt;=n);的时间复杂度为()
You need a___ in your resume to hold your reader’s attention()
执行下面程序后的结果是()。void fun(){int i, s=0;for (i=5; i<6; i++)、{s=s+i;}printf(“%d”, s);}main(){fun();}
int i,s=0;for(i=1;i<4;i++){s=s+i;}程序执行后s等于()
若s、i均为整型变量,执行下列程序段后s的值为 【11】 。 S=0 i=1 DOS=S+i ┊i=i+1 Loop Until i>5
以下程序的运行结果是 i,s=1,0 while i<10: if i%2==0:continue else:s=s+i i=i+1 print(s)