T ask 3: L i s t e n t o t h e c o n v e r s a tio n s an d c h oo s e t h e b e s t a ns w e r t o e a c h q u e s tio n . 02_Task 3.mp3:/js/editor20150812/dialogs/attachment_new/fileTypeImages/icon_mp3.gif
4 Complete the words.► h u m a n human1 p r d c t b l e ____2 d i s e a r ____3 f m n e ____4 h r m f l ____5 a t m o e r e ____6 e n v r o m n t ____7 p l l t n ____8 l q u d ____9 d s s e ____10 c l m t ____
_________i s a n alternativ e t o hig h school . It s objectiv e i s t o trai n student s i n the i n comprehensiv e vocationa l capabilit y , preparin g the m fo r th e fron t rank s o f production, services, technical services, and management.
______ T emple , locate d 2 1 kilometre s eas t o f Luoyan g, Hena n Province , w as t h e f i rs t o f f i c i a lly bu ilt Buddh i s t tem p le in Ch i n a in t h e Ea s te r n H an Dyn a s t y .
1 Complete the words.► h a i r c u t haircut1 f r _ _ _ e ____2 s _ _ s s _ r _ ____3 h _ _ r s t _ _ e ____4 h _ _ r d _ _ _ r ____5 p _ _ t _ n g ____6 t _ _ m ____7 c _ l _ _ r ____8 b l _ w – d r _ ____
有以下程序 #include void fun(int a, int b) { int t; t=a; a=b; b=t; } main() { int c[10]={1,2,3,4,5,6,7,8,9,0), i; for (i=0; i<10; i+=2) fun(c[i], c[i+l]); for (i=0; i<10; i++) printf(\%d,\, c[i]); printf(\\\n\); } 程序的运行结果是( )。
4 Complete the words.► l u n g c a n c e r lung cancer1 m _ m _ r _ l _ _ s s ____2 a r _ r _ t i c ____3 b r _ _ n ____4 b l _ _ _ ____5 s t r _ _ e ____6 h _ _ r t d _ s _ _ s e ____7 d _ s _ b _ l _ t y ____
1 Complete the words.► k n i c k e r s knickers1 _ n d _ r w _ _ r ____2 m _ t _ r _ _ l ____3 s l _ _ v _ ____4 t i _ _ t s ____5 s _ _ d e ____6 n _ c k l e ____7 b l _ _ s e ____8 e a _ _ i n s ____9 v _ _ t ____10 b _ _ t t _ n ____
T ask 2: Listen to the short dialogs and choose t h e bes t answe r t o eac h question. 06_Task 2.mp3:/js/editor20150812/dialogs/attachment_new/fileTypeImages/icon_mp3.gif
下面程序的运行结果是( )。# include < stdio. h>mt main( ){ int a[9] = {0,6,12 ,18,42,44,52,67,94};int x=52,i,n=9,m;i= n/2+1;m= n/2;while(m! =0)if(xa[i]){ i=i+m/2+1; m=m/2;}else break;printf(\The index is:%d\n\,t);return 0;}
以下程序的输出结果是#includeint main(void){int b[3][3]={0,1,2,0,1,2,0,1,2},i,j,t=1;for(i=0;i<3;i++)for(j=i;j<=i;j++)t=t+b[i][b[j][j]];printf(\%d\\n\,t);return 0;}
有以下程序inculde <stdio.h>Main(){ int B[3][3]={0,1,2, 0,1,2,0,1,2},i,j,t+1;For (i=0;i<3;i++)For (j=1;j<=1;j++) t + =B[i]B[[j][i]];printF(“%d\n”,t);}程序运行后的输出结果是
有以下程序: include<stdio.h> main() {int b[3][3]=(0,1,2,0,1,2,0,1,2},i,j,t=l;
葡语中的字母为A、B、C、D、E、F、G、H、I、J、K、L、M、N、O、P、R、S、T、U、V、W、X、Y、Z。对吗?
一螺绕环的中心周长为l=10cm,环上紧密地绕有N=50匝的线圈,线圈中通有I=0.2 A的电流。(1)求管内的磁感应强度的大小B0和磁场强度的大小H。;(2)若管内充满相对磁导率μr=3000的磁介质,那么管内的B和H是多少?(3)磁介质内由导线中的电流产生的B0和由磁化电流产生的B'各是多少?
下面代码的功能是在屏幕上输出以下内容 0 1 3 程序中空白处缺少的代码由下列选项给出,其中有一个不能满足题目要求,请将其找出。 include <stdio.h> int main() { int b[3][3]={0,1,2,0,1,2,0,1,2},i,j,t=0; for(i=0;i<3;i++) for(j="i;j&lt;=i;j++)" { t="t+____________;" printf("%d\n",t); } return 0;>
图示电路中,已知R<sub>1</sub>=1Ω,L<sub>1</sub>=L<sub>2</sub>=1 H,M=0.5 H,i<sub>1</sub>(0_)=0,u<sub>n</sub>(t)= =10e(t)V,求u
恺撒密码是古罗马恺撒大帝用来对军事情报进行加解密的算法,它采用了替换方法对信息中的每一个英文字符循环替换为字母表序列中该字符后面的第三个字符,即,字母表的对应关系如下: 原文:A B C D E F G H I J K L M N O P Q R S T U V W X Y Z 密文:D E F G H I J K L M N O P Q R S T U V W X Y Z A B C 对于原文字符P,其密文字符C满足如下条件:C=(P+3) mod 26 上述是凯撒密码的加密方法,解密方法反之,即:P=(C-
请读程序:include<stdio.h>f(int b[],int n){int i,r;r=1;for(i=0;i<=n;i++)r=r*b[i];return r;}main(){int x,a[]={2,3,4,5,6,7,8,9};x=f(a,3);print
有以下程序include<stdio.h>defineN4voidfun(inta[][N],intb[]){inti;for(i=0;i<N;i++)b[i]=a[i][i];}main{intx[][N]={{1,2,3},{4},{5,6,7,8},{9,10}},y[N],i;fun(x,y);for(i=0;i<N;i++)printf(%d,,y[i]);p
nǚ:huá lóngzhōu bǐsài mǎshàng kāishǐ le, wǒmen zǒu guòqu kàn kan ba。女:划龙舟比赛马上开始了,我们走过去看看吧。nán:tài hǎo le, wǒ tèbié xiǎng cānjiā, nǐ zhīdào zěnme bàomíng ma?男:太好了,我特别想参加,你知道怎么报名吗?nǚ:dāngrán la, xiànchǎ
include <stdio.h>void main(){int b,i;b=0;for(i=1;i<5;i++){switch(i){case 0:case 3:b+=2;case 1:case 2:b+=3;default:b+=5;}}printf(""%d\n"",b);}以上程序执行后,输出b的值是
给定一组记录,其关键码为字符,记录的插人顺序为(C,S,D,T,A,M,P,I,B,W,N,G,U,R,K,E,H,O,L,J),给出插入这些记录后的4阶B+树。
Yǒu měi de jiā hěn dà ,yòu . 2、Yǒu měi de jiā yǒu 、liǎng gè fáng jiān 、chú fáng hé . 3、Liǎng ge fáng jiān , shì Yǒu měi de ,yòu biān de shì tā péng yǒu de . 4、 bú tài guì.