设 ,是来自总体N（0,σ²)的简单随机样本,则可以构造未知参数σ²的无偏估计量（或数学

已知X₁,X₂,…,X₆是来自正态总体N(0,σ²)的简单随机样本.且 <img src='https://img2.soutiyun.com/ask/2020-08-10/96589894787285.png' /> 求a和n. 解题提示 根据t分布的定义来求.

A.(30.88，32.63) B.(31.45，31.84) C.(31.62，31.97) D.(30.45，31.74)

设<img src='https://img2.soutiyun.com/ask/2020-11-18/974563559946235.png' />为来自总体N(μ,σ2)的简单随机样本,<img src='https://img2.soutiyun.com/ask/2020-11-18/974563569546784.png' />为样本均值,已知<img src='https://img2.soutiyun.com/ask/2020-11-18/974563615737426.png' />是σ²的无偏估计(或ET=σ²),则常数C必为（） A.<img src='https://img2.soutiyun.com/ask/2020-11-18/974563625160965.png' /> B.<img src='https://img2.soutiyun.com/ask/2020-11-18/974563634424495.png' /> C.<img src='https://img2.soutiyun.com/ask/2020-11-18/974563643532016.png' /> D.<img src='https://img2.soutiyun.com/ask/2020-11-18/974563651352464.png' />

设X₁，X₂，...，X_n是取自正态总体N(μ，σ²)的样本，μ与σ均未知，则σ²的矩估计量<img src='https://img2.soutiyun.com/ask/2021-01-05/978692195864823.jpg' />为()。 <img src='https://img2.soutiyun.com/ask/2021-01-05/978692212468773.jpg' />

设<img src='https://img2.soutiyun.com/ask/2020-10-05/970778702595939.jpg' />是来自总体N(μ,σ²)的容量为n的两个相互独立的简单随机样本的均值,试确定n.使得两个样本均值之差的绝对值超过σ的概率大约为0.01.

设总体X~N(μ，σ²)，X₁，...，X₁₀是来自X的样本。 (1)写出X₁，...，X₁₀的联合概率密度； (2)写出<img src='https://img2.soutiyun.com/ask/2020-11-24/975076412778141.jpg' />的概率密度。

设X₁，…，X₁₆是来自N(μ，σ²)的样本，经计算<img src='https://img2.soutiyun.com/ask/2020-08-04/96539878216653.png' />试求<img src='https://img2.soutiyun.com/ask/2020-08-04/965398802528695.png' />

设X₁，X₂，...X₂₀是来自正态总体N(0，0.3²)的一个样本，求： <img src='https://img2.soutiyun.com/ask/2020-07-31/965060656688145.png' />

设X₁，X₂，...X_n(n≥2)为来自正态总体N(0，1)的简单随机样本，<img src='https://img2.soutiyun.com/ask/2020-07-31/965062468168756.png' />为样本均值，S²为样本方差，则正确的是()。 <img src='https://img2.soutiyun.com/ask/2020-07-31/965062477119268.png' />

设总体X服从正态分布N(μ，σ²)(σ＞0).从该总体中抽取简单随机样本<img src='https://img2.soutiyun.com/ask/2020-11-18/974556174244797.png' />,其样本均值为<img src='https://img2.soutiyun.com/ask/2020-11-18/974556183114305.png' />求统计量<img src='https://img2.soutiyun.com/ask/2020-11-18/974556216981242.png' />的数学期望EY.

设样本X₁，X₂，...，X_n取自正态总体N(μ，σ₀²)(σ₀²已知)，对检验假设H₀：μ=μ₀，H₁：μ＞μ₀的问题，取拒绝域<img src='https://img2.soutiyun.com/ask/2020-12-30/978192934116923.jpg' /> (1)求此检验犯第一类错误的概率为a时，犯第二类错误的概率β，并讨论它们之间的关系； (2)设μ₀=0.5，σ₀²=0.04，α=0.05，n=9，求μ=0.65时不犯第二类错误的概率。

设<img src='https://img2.soutiyun.com/ask/2020-11-18/974563559946235.png' />是来自总体X~N(μ,σ²)的样本,其中μ已知,σ²＞0为未知参数,样本均值为<img src='https://img2.soutiyun.com/ask/2020-11-18/974563569546784.png' />,则σ²的最大似然估计量为（） A.<img src='https://img2.soutiyun.com/ask/2020-11-18/97456369359988.png' /> B.<img src='https://img2.soutiyun.com/ask/2020-11-18/97456370198636.png' /> C.<img src='https://img2.soutiyun.com/ask/2020-11-18/974563711307893.png' /> D.<img src='https://img2.soutiyun.com/ask/2020-11-18/974563720210402.png' />

设总体X服从正态分布N(μ, σ²) (σ＞0),从总体中抽取简单随机样本<img src='https://img2.soutiyun.com/ask/2020-08-09/965846856163765.png' />，其样本均值为<img src='https://img2.soutiyun.com/ask/2020-08-09/965846906898667.png' />求统计量<img src='https://img2.soutiyun.com/ask/2020-08-09/965846894326948.png' /><img src='https://img2.soutiyun.com/ask/2020-08-09/965846932984159.png' />的数学期望。

设X₁，X₂，...，X₁₅是来自正态总体X~N(0，2²)的样本，记<img src='https://img2.soutiyun.com/ask/2020-11-26/97524949946665.jpg' />，求Y的分布。

设<img src='https://img2.soutiyun.com/ask/2020-11-18/974556250959185.png' />是来自总体X~N(μ，σ²)的简单随机样本,记<img src='https://img2.soutiyun.com/ask/2020-11-18/974556263092879.png' /> 求(I)E(Y); (II)D(Y).

设总体X~N(0,σ²),X₁,X₂,...,X_n是来自总体X的一个样本. <img src='https://img2.soutiyun.com/ask/2020-09-30/970341001201029.png' />

设X₁,X₂,...,X_n是总体N(μ,σ²)的一个样木,求k使<img src='https://img2.soutiyun.com/ask/2020-09-30/97034115297571.png' /><img src='https://img2.soutiyun.com/ask/2020-09-30/970341180409279.png' />σ的无偏估计.

设总体X~N(μ,σ²)，μ,σ²,未知，X1,...,Xn是X的简单随机样本，则μ的置信水平至少为0.90的置信区间为()。 <img src='https://img2.soutiyun.com/ask/2021-01-07/978868222705221.jpg' />

设X₁,X₂,…,X_n是来自正态总体N(μ,σ²)的简单随机样本,记 <img src='https://img2.soutiyun.com/ask/2020-08-10/965898914993969.png' />i=1,2,...,n.求Y_i服从的分布及相应的概率密度函数. 解题提示 相互独立的正态分布的随机变量的线性组合仍服从正态分布.

设<img src='https://img2.soutiyun.com/ask/2020-11-18/974555447058205.png' />为来自总体N(μ,σ²)(σ＞0)的简单随机样本;令<img src='https://img2.soutiyun.com/ask/2020-11-18/974555483547292.png' />则（） A.<img src='https://img2.soutiyun.com/ask/2020-11-18/974555514524064.png' /> B.<img src='https://img2.soutiyun.com/ask/2020-11-18/974555523007549.png' /> C.<img src='https://img2.soutiyun.com/ask/2020-11-18/974555531280022.png' /> D.<img src='https://img2.soutiyun.com/ask/2020-11-18/974555539864513.png' />

设X₁，X₂，...，X₉是来自正态总体X~N(0，2²)的样本，求a，b，c使得：<img src='https://img2.soutiyun.com/ask/2020-11-26/975249407058365.jpg' />

设总体x服从N(0,σ²),从总体中取出一个容量为6的样本(X₁,X₂,...,X₆),令Y=(X₁+X₂+X₃)²+(X₄+X₅+X₆)²试确定常数c,使得cY服从x²分布.

设<img src='https://img2.soutiyun.com/ask/2020-11-18/974556800064592.png' />为来自正态总体N(0,σ²)的简单随机样本,则统计量<img src='https://img2.soutiyun.com/ask/2020-11-18/974556809002103.png' />服从的分布为（） A.F(1,1) B.F(2,1) C.t(1) D.t(2)