Examine the description of the EMPLOYEES table: EMP_ID NUMBER(4) NOT NULL LAST_NAME VARCHAR2(30) NOT NULL FIRST_NAME VARCHAR2(30) DEPT_ID NUMBER(2) Which statement produces the number of different departments that have employees with last name Smith? ()
Examine the following command: CREATE TABLE (prod_id number(4), Prod_name varchar2 (20), Category_id number(30), Quantity_on_hand number (3) INVISIBLE); Which three statements are true about using an invisible column in the PRODUCTS table?()
在Excel2002中,AVERAGE(number1,number2,…)返回()。
Examine the description of the EMPLOYEES table: EMP_ID NUMBER(4) NOT NULL LAST_NAME VARCHAR2(30) NOT NULL FIRST_NAME VARCHAR2(30) DEPT_ID NUMBER(2) Which statement produces the number of different departments that have employees with last name Smith?()
ACL命令acl[number]acl-number[match-order{autoconfig}],其中acl-number用于指定访问控制列表的编号,基本访问控制列表的acl-number取值范围是()
Lifeboats are numbered().Odd numbers to starboard and even numbers to port.
下面程序的运行结果是?main() {int x=30;int[] numbers=new int[x];x=60;System.out.println(numbers.length);}
Numbers include cardinal numbers and ordinal numbers.
the binary number 11011101 is equal to the decimal number
Java认为变量number与Number是相同的
SUM(number 1, number 2, ……)是_____函数。
下面代码的执行结果是()。1defDemo(number):2number*=43print(Demo(4))
在Telnet中应用如下ACL:【acl number 2000】 【rule 5 deny source 172.16.105.30】 【rule 10 deny source 172.16.105.40】 【rule 15 deny source 172.16.105.50 rule 20 permit】 下列说法正确的是()
下面是路由器A的BGP部分配置,根据给出的配置,描述错误的是【RouterA】 bgp 10【RouterA-bgp】 Router-ID 1.1.1.1 【RouterA-bgp】 peer 200.1.4.2 as as-number 30 【RouterA-bgp】 peer 200.1.4.2 as as-number 20 【RouterA-bgp】 import-route direct()
SUM(number1,number2, …) 返回单元格区域中()
下面是路由器A的BGP部分配置,则根据配置,判断下列选项描述正确的是:()[RouterA] bgp 10[RouterA-bgp] router-id 1.1.1.1[RouterA-bgpl peer 200.1.4.2 as-number 30[RouterA-bgpI peer 200.1.2.2 as-number 20[RouterA-bgp]import-route direct
Suppose that a price of $30 per month, there are 30,000 subscribers to cable television in Small Town. If Small Town Cablevision raises its price to $40 per month, the number of subscribers will fall
Examine the structure of the EMPLOYEES table:Column name Data type RemarksEMPLOYEE_ID NUMBER NOT NULL, Primary KeyEMP_NAME VARCHAR2(30)JOB_ID VARCHAR2(20) NOT NULLSAL NUMBERMGR_ID NUMBER References EMPLOYEE_ID columnDEPARTMENT_ID NUMBER Foreign key to DEPARTMENT_ID columnof the DEPARTMENTS tableYou need to create a view called EMP_VU that allows the users to insert rows through the view. Which SQL statement, when used to create the EMP_VU view, allows the users to insert rows?()
int number[10]={2};printf(“%d”,number[1]); 以上程序的输出结果是()
Directions: The following is list of terms. After reading it, you are required to find the items equivalent ....... (相同) those given in Chinese in the table below. Then you should put the corresponding letters in the brackets numbered 26 through 30.
如果Number=3,请指出下列语句的真与假。 If Number = 3, point out the truth and false of the following statements. Int(Number * Number) = Number * Number
如果Number=3,判断下列命题的真假。 If Number = 3, judge the truth of the following propositions. (Number*Number)>=(2*Number)
Examine the structure of the EMPLOYEES and DEPARTMENTS tables:EMPLOYEESColumn name Data type RemarksEMPLOYEE_ID NUMBER NOT NULL, Primary KeyEMP_NAME VARCHAR2 (30)JOB_ID VARCHAR2 (20)SALARY NUMBERMGR_ID NUMBER References EMPLOYEE_ID COLUMNDEPARTMENT ID NUMBER Foreign key to DEPARTMENT IDcolumn of the DEPARTMENTS tableDEPARTMENTSColumn name Data type RemarksDEPARTMENT_ID NUMBER NOT NULL, Primary KeyDEPARTMENT_NAME VARCHAR2(30)MGR_ID NUMBER References MGR_ID column of theEMPLOYEES tableEvaluate this SQL statement:SELECT employee_id, e.department_id, department_name,salaryFROM employees e, departments dWHERE e. department_id = d.department_id;Which SQL statement is equivalent to the above SQL statement?()
Examine the structure of the EMPLOYEES table:Column name Data type RemarksEMPLOYEE_ID NUMBER NOT NULL, Primary KeyLAST_NAME VARCNAR2(30)FIRST_NAME VARCNAR2(30)JOB_ID NUMBERSAL NUMBERMGR_ID NUMBER References EMPLOYEE_ID columnDEPARTMENT_ID NUMBERYou need to create an index called NAME_IDX on the first name and last name fields of the EMPLOYEES table. Which SQL statement would you use to perform this task?()