Why switch grass and Miscanthus were taken as energy plant？

A . to prevent unauthorized Telnet access to a switch port B . to limit the number of Layer 2 broadcasts on a particular switch port C . to prevent unauthorized hosts from accessing the LAN D . to protect the IP and MAC address of the switch and associated ports E . to block unauthorized access to the switch management interfaces over common TCP port

A . It has more than one interface that is connected to the root network segment. B . It is running RSTP while the elected root bridge is running 802.1d spanning tree. C . It has a higher MAC address than the elected root bridge. D . It has a higher bridge ID than the elected root bridge.

A . in order to optimize the path that frames take from source to destination B . to increase the priority so a designated port will become a root port C . to increase the BID, so the switch is more likely to become root bridge D . in order to allow VLANs to be sent from one switch to another across a single link E . to force a given switch to become an STP server

A . goes out B . go out C . to go out D . going out

A .  Port 3/12 was already up and forwarding before the loop was created. B .  Port priority is based on lowest priority and lowest port number. C .  You connected the wire on port 3/18 last. D .  None of the above， it is purely random.

A . Broadcasts only use network layer addressing. B . A broadcast frame is never forwarded by a switch. C . A broadcast address will never be the source address of a frame. D . Broadcast addresses use an incorrect format for the switching table. E . Broadcast frames are never sent to switches.

A . Latency fluctuates regardless of frame size. B . The switch receives the complete frame before beginning to forward it. C . Latency through the switch varies with frame length. D . The switch checks the destination address upon receipt of headers.

A . to prevent unauthorized Telnet access to a switch port B . to limit the number of Layer 2 broadcasts on a particular switch port C . to prevent unauthorized hosts from accessing the LAN D . to protect the IP and MAC address of the switch and associated ports E . to block unauthorized access to the switch management interfaces over common TCP port

A . Switch A ,because it has the lowest MAC address B . Switch C,because it has the lowest priority C . Switch B,because it has the highest MAC address D . Switch C,because it is the most centrally located switch E . Switch A,because it is the most centrally located switch F . Switch D,because it has the highest priority

A . The MD5 digests do not match B . Switch CK-P1S1 is in transparent mode C . The passwords do not match D . The VTP domains are different

A . to ensure a loop-free topology B . to protect against user-side loops C . in order to support business applications D . because of the risk of lost connectivity without STP E . for the most deterministic and highly available network topology

A . Port 3/12 was already up and forwarding before the loop was created. B . Port priority is based on lowest priority and lowest port number. C . You connected the wire on port 3/18 last. D . None of the above， it is purely random.

A．Right B．Wrong C．Not mentioned

A．Right B．Wrong C．Not mentioned

A. helps B. inspires C. prevents D. stops

A．True B．False C．Not mentioned

<img src='https://img2.soutiyun.com/shangxueba/ask/64347001-64350000/64349888/0398b672a5fe93231b8d66737518db9a.png' /> A.It has more than one interface that is connected to the root network segment. B.It is running RSTP while the elected root bridge is running 802.1d spanning tree. C.It has a higher MAC address than the elected root bridge. D.It has a higher bridge ID than the elected root bridge.

A．Oliver Wendell Holmes B．Henry Wadsworth Longfellow C．Ralph Waldo Emerson D．Henry David Thoreau