设f(x)单调下降,如果导数f'(x)在[0,+∞)上连续,那末积分收敛

设f(x)单调下降,<img src='https://img2.soutiyun.com/ask/2021-01-25/98043920905966.png' />如果导数f'(x)在[0,+∞)上连续,那末积分<img src='https://img2.soutiyun.com/ask/2021-01-25/980439230777902.png' />收敛

时间:2024-04-03 14:25:54

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