设L是圆周x<sup>2</sup>+y<sup>2</sup>=a<sup>2</sup>(a>0)负向一周,则曲线积分<img src='https://img2.soutiyun.com/shangxueba/ask/17682001-17685000/17682241/2015102616160584974.jpg' />(x<sup>3</sup>-x<sup>2</sup>y)dx+(xy<sup>3</sup>-y<sup>3</sup>)dy的值为:()
A.πa<sup>4</sup>
B. -πa<sup>4</sup>
C. -(π/2)a<sup>4</sup>
D. (π/2)a<sup>4</sup>
时间:2023-06-29 16:03:10
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