设fe(x)可导,且fk(x)≠0,k=1,2,....,n,证明:

设fe(x)可导,且fk(x)≠0,k=1,2,....,n, <img src='https://img2.soutiyun.com/ask/2021-01-18/979833162387778.png' />证明:<img src='https://img2.soutiyun.com/ask/2021-01-18/97983317623057.png' />

时间:2024-04-03 12:23:34

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