已知y1(x)和y2(x)是方程y''+p(x)y'+Q(x)y=0的两个线性无关的特解, Y1(x)和Y2 (x)分别是方程y''+p(x)y'+Q(x)y=R1(x)和y''+p(x)y'+Q(x)y=R2(x)的特解。那么方程y''+p(x)y'+Q(x)y=R1(x)y+R2(x)的通解应是()

A.c1y1+c2y2B. c1Y1(x)+c2Y2(x) C.c1y1+c2y2+Y1(x) D. c1y1+c2y2+Y1(x)+Y2(x)

时间:2023-08-20 11:52:10

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