求微分方程y'＋ytanx=sin2x的通解。

A . y=C +C x+C e +C e B . y=C cosx+C sinx+C x+C C . y=C +C X+C e +C e D . y=C e +C e +C cosx+C sinx

A .https://assets.asklib.com/images/image2/2017051115262332611.png B .https://assets.asklib.com/images/image2/201705111526331392.png C .https://assets.asklib.com/images/image2/2017051115263940123.png D .https://assets.asklib.com/images/image2/2017051115264827726.png

A .https://assets.asklib.com/psource/1472202560549010600.png B .https://assets.asklib.com/psource/1472202567045034775.png C .https://assets.asklib.com/psource/1472202580719008560.png D .https://assets.asklib.com/psource/1472202587061009148.png

A .https://assets.asklib.com/psource/2015103009085663303.jpg B .https://assets.asklib.com/psource/2015103009091011647.jpg C .https://assets.asklib.com/psource/2015103009092395807.jpg D .https://assets.asklib.com/psource/2015103009093643077.jpg

A . y=C e +C e B . y=e （C +C x） C . y=C e +C e D . y=C e +C e

A．y=e^x+e^-x B．y=e^x-e^-x C．y=C₁e^x+C₂e^-x D．y=C₁e^2x+C₂e^-2x

A.sinx+C1x+C2 B.sinx+C1+C2 C.-sinx+C1x+C2 D.-sinx+C1+C2

求微分方程y"-4y=e^x2的通解。

求下列微分方程的通解：16y"-24y’+9y=0

A．y=cos(x+c1)+c2 B．y=sin(x+c1)+c2 C．y=-In|cos(x+c1)|+c2 D．y=-In|sin(x+c1)|+c2

<img src='https://img2.soutiyun.com/ask/2020-10-27/972663120445965.png' />

A．－sinx＋C1＋C2 B．－sinx＋C1x＋C2 C．－cosx＋C1x＋C2 D．sinx＋C1x＋C2

<img src='https://img2.soutiyun.com/ask/2020-10-27/97267134023011.png' />